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收藏本站 提供:電熱管價格和電熱管規格型號大全,還提供電熱管接線、選型的問題,特耐佳電加熱器高端電熱供應商。

電熱管計算舉例

今日出廠產品展示及部分報價

單端加熱管

單端加熱管

電流的巨細直接與功率有關,也與電壓、相別、功率因數(又稱力率)等有關。通常有公式可核算。因為工廠常用的都是380/220V三相四線體系,因而能夠依據功率的巨細直接算出電流。 在380三相時(功率因數0.8左右),電動機每KW的電流約為2A。行將“KW數加一倍”(乘2)就是電流A。這電流也稱電動機的額定電流。 (例1)5.5KW電動機按“電力加倍”算得電流為11A。 (例2)40KW水泵電動機按“電力另倍”算得電流為80A。 電熱是指用電阻加熱的電阻爐等。三相380V的電熱設備,每KW的電流為1.5A。行將“Kw數加一半”(乘1.5)就是電流A。 (例3)3KW電加熱器按“電熱加半”算得電流為4.5A。 (例4)15KW電加熱爐按“電熱加半”算得The electric heater power calculation, calculation of a premise  general electric heater in the following three steps design 1 maintain medium temperature yesterday the actual needs of the maintenance temperature power 2 calculated from the initial temperature of the heating in a specified period of time to set the temperature to the required power of 3 according to the above two results context selection heater type and quantity. The maximum value of total power take the above two kinds of power and the 1.2 coefficient. Medium kg\/h 2 initial heating power KW=C2M3 △ T\/864+P formula  1 to maintain the temperature of the medium in the pump need  M3 per hour increased the required power KW = (C1M1 △ T △ T + C2M2) / 864\/P + P\/2 type of  C1C2 were containers and medium heat Kcal\/Kg ℃ exergy M1M2 respectively. Containers and medium quality Kg exergy △ T is the initial temperature of the heating container to the desired temperature time h exergy P final temperature of heat quantity Kw exergy two, electric heating performance curve is below some frequently used to calculate the electric heating of the performance curves for the temperature and the initial temperature of the difference ℃ exergy H. Three, the electric heater design example of calculation by a open container context size width 500mm context 1200mm context 600mm for high context container weight 150Kg. Built-in water deep container 500mm height are all around 50mm insulation materials for silicate yesterday. Water for 3 hours from 15 ℃ heated to 70 ℃ yesterday and then from the container extraction for 20kg\/h at 70 ℃ water deep and add the same weight of water. In order to meet the need of power much desired temperature. Technical data by 1, the proportion of water by the 1000kg\/m3 2, the specific heat of water by 1kcal\/kg at 3 ℃, steel heat  0.12kcal\/kg at 4 ℃, water at 70 ℃ surface loss of 4000W\/m2 5, the insulation layer exergy loss at 70 ℃ 32W\/m2 6, 0.6m2 7, the area of the container by the insulation layer of the area by 2.52m2 the initial heating power required by the water in the container heated  C1M1 △ T = 1 × 0.5 x 1.2 x 0.5 x 1000 exergy x (70  15) = 16500 kcal vessel’s heated  C2M2 △ T = 0.12 * 150 * (70  15) = 990 kcal average water surface heat loss by 0.6m2 * 4000W\/m2 * 3H * 1\/2 * 864\/1000 = 3110.4 kcal average insulation heat loss by 2.52m2 * 32W\/m2 * 3H * 1\/2 * 864\/1000 = 104.5 kcal (considering the rich content 20%) initial heating needs of energy required for the power of  heating needs  “16500 + 990 + 3110.4 + 104.5 x 1.2 = 70258.8 kcal\/kg ℃ when the work of the supplementary heat water  20kg\/H × (70 × 1kcal\/kg ℃ yesterday 15) = 1100kcal water surface heat loss  0.6m2 * 4000W\/m2 * 1H * 864\/1000 = 2073.6 kcal insulation heat loss  2.52m2 * 32W\/m2 * 1H * 864\/1000 = 69.67 kcal  considering rich volume 20% Power heating energy for  at 1100 + 2073.6 + 69.6 x 1.2 = 6486.54 kcal\/kg ℃ heating for power energy heater selection needs power  6486.54 / 864 / 1 = 7.5 kW initial heating than when working with at least 27.1kw. The heater power ultimately selected for 35kw電流為22.5A。這口訣應不專指電熱,關于白治燈為主的照明也適用。盡管照明的燈泡是單相而不是三相,但對照明供電的三相四線仍屬三相。只需三相大體平衡也可這樣核算。此外,以KVA為單位的電器(如變壓器或整流器)和以KVar為單位的移相電容器(進步功率因數用)也都適用。既是說,這后半句盡管說的是電熱,但包含一切KVA.KVar為單位的用電設備,以及以KW為單位的電熱和照明設備。 (例5)12Kw的三相(平衡時)照明干線按“電熱加半”算得電流為18A。 (例6)30KVA的整流器按“電熱加半”算得電流為45A(指380V三相溝通側)。 (例7)100KVar的移相電容器(380v三相)按“電熱加半”算得電流為150A。 (例8)在380/220V三相四線體系中,單相設備的兩條線,一條接相線 而另一條接零線的(如照明設備)為單相220V用電設備。這種設備的功率因數大多為1,因而,口訣便直接闡明“單相(每)KW4.5A”。核算時,只需“將千瓦數乘4.5”就是電流A。 同上面相同,它適用于一切以KVA為單位的單相220V用電設備,以及以KW為單位的電熱及照明設備,并且也適用于220V的直流。 (例9)1000W投光燈按“單相千瓦、4.5安”算得電流為4.5A。關于電壓更低的單相,口訣中沒有說到。能夠取220V為規范,看電壓下降多少,電流就反過來增大多少。比方36V電壓,比220V為規范來說,它下降到1/6,電流就應增大到6倍,即每KW的電流為6×4.5=27A。比方36V、60W的行燈每只電流為0.06×27=1.6A,5只便共有8A。當前電氣照明也廣泛選用熒光燈、高壓水銀熒光燈、金屬鹵化物燈等,因為它們的功率因數很低(約為0.5),因而不能同口訣①、②中的白織燈照明相同處置。這時,可把KW換算成KVA后,再按本口訣核算。也能夠直接記?。核鼈兠?Kw在三相380V時為3A;在單相220V時為9A。因而例5若為熒光燈照明,電流將為36A;例10中若為高壓水銀熒光燈照明,電流將為9A。 (例10)在380/220三相四線體系中,單相設備的兩條線都接到相線上的,習慣上稱為單相380V用電設備(實踐是接在兩相上)。 這種設備當以KW為單位時,功率大多為1,口訣也直接闡明:“單相380,電流兩A半”。它包含以KVA為單位的380V單相設備。核算時,只需“將千瓦或千伏安數乘2.5”就是電流A

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女人阴性道图片真人18